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#1
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7.0% .0% 0.0% 94.0% |
#2
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It would have been helpful if you'd said so at the outset. On its own, the process won't work in tables. You could, however, use a series of wildcard Find/Replace expressions, where:
Find = .[0-9]% Replace = ^s^& Find = ([0-9])^s(.[0-9]%) Replace = \1\2 This will now leave you with the .0%s with a non-breaking space before them, so you can then do a wildcard Find for just those, with: Find = ^s.[0-9]% Quote:
__________________
Cheers, Paul Edstein [Fmr MS MVP - Word] |
#3
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But thank you again for your help. |
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