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Hi! The folowing code will replace all 3 and more paragraph signs with two ones in the selected range:
Code:
Sub Deleemptyparagraphs() selection.Find.ClearFormatting selection.Find.Replacement.ClearFormatting With selection.Find .text = Chr(13) & "{3;}" .Replacement.text = "^p^p" .Forward = True .Wrap = wdFindStop .Format = False .MatchWildcards = True .MatchAllWordForms = False .MatchSoundsLike = False End With selection.Find.Execute Replace:=wdReplaceAll End Sub |
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