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Thread Tools | Display Modes |
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#1
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Split from: https://www.msofficeforums.com/word-...-pictures.html
My intention is that if more than one image was selected, one table by image. Also, I have added a line what I like it, but and I would like to remove only the outer edge, is it possible? I would like it to stay like this: Anyway, I would like that if I choose several images, they have space between them. I don't know where I have to put the line of code to create a space between one table and the next. Code: Code:
Sub AddPics()
Application.ScreenUpdating = False
Dim Stl As Style, i As Long, j As Long, c As Long, r As Long, NumCols As Long, iShp As InlineShape
Dim oTbl As Table, TblWdth As Single, StrTxt As String, RwHght As Single, ColWdth As Single
On Error GoTo ErrExit
NumCols = 1 'CLng(InputBox("Cuantas columnas por fila?"))
RwHght = CentimetersToPoints(8) '(CSng(InputBox("¿Altura maxima de la fila?")))
On Error GoTo 0
'Selecciona e inserta fotos
With Application.FileDialog(msoFileDialogFilePicker)
.Title = "Seleccion de imagenes y click en Abrir"
.Filters.Add "Imagenes", "*.gif; *.jpg; *.jpeg; *.bmp; *.tif; *.png"
.FilterIndex = 2
If .Show = -1 Then
'Crea un Estilo de parrafo con 0 espacios antes/despues y alineado al centro.
With ActiveDocument
On Error Resume Next
Set Stl = .Styles("TblPic")
If Stl Is Nothing Then Set Stl = .Styles.Add(Name:="TblPic", Type:=wdStyleTypeParagraph)
On Error GoTo 0
With .Styles("TblPic").ParagraphFormat
.Alignment = wdAlignParagraphCenter
.KeepWithNext = True
.SpaceAfter = 0
.SpaceBefore = 0
End With
End With
'Agregue una tabla de 2 filas por NumCols-column para colocar las imágenes
Set oTbl = Selection.Tables.Add(Range:=Selection.Range, NumRows:=2, NumColumns:=NumCols)
With ActiveDocument.PageSetup
TblWdth = .PageWidth - .LeftMargin - .RightMargin - .Gutter
ColWdth = CentimetersToPoints(15) 'TblWdth / NumCols
End With
With oTbl
.AutoFitBehavior (wdAutoFitFixed)
.TopPadding = 0
.BottomPadding = 0
.LeftPadding = 0
.RightPadding = 0
.Spacing = 0
.Columns.Width = ColWdth
.Borders.Enable = True
End With
CaptionLabels.Add Name:="Fotografía nº"
For i = 1 To .SelectedItems.Count Step NumCols
r = ((i - 1) / NumCols + 1) * 2 - 1
'Formato de filas
Call FormatRows(oTbl, r, RwHght)
For c = 1 To NumCols
j = j + 1
ActiveDocument.Tables(1).Spacing = 9
'Inserta la foto
Set iShp = ActiveDocument.InlineShapes.AddPicture( _
FileName:=.SelectedItems(j), LinkToFile:=False, _
SaveWithDocument:=True, Range:=oTbl.Cell(r, c).Range)
With iShp
.LockAspectRatio = True
If (.Width < ColWdth) And (.Height < RwHght) Then
.Width = ColWdth
If .Height > RwHght Then .Height = RwHght
End If
End With
'Obtener el nombre de la imagen para el pie de foto
StrTxt = Split(.SelectedItems(j), "\")(UBound(Split(.SelectedItems(j), "\")))
StrTxt = ": " & Split(StrTxt, ".")(0)
'Inserta el título Caption en la fila debajo de la imagen
With oTbl.Cell(r + 1, c).Range
.InsertBefore vbCr
.Characters.First.InsertCaption _
Label:="Fotografía nº", Title:=StrTxt, _
Position:=wdCaptionPositionBelow, ExcludeLabel:=False
.Characters.First = vbNullString
.Characters.Last.Previous = vbNullString
End With
'Salir cuando hayamos terminado
If j = .SelectedItems.Count Then Exit For
Next
'Agregue filas adicionales según sea necesario
If j < .SelectedItems.Count Then
oTbl.Rows.Add
oTbl.Rows.Add
End If
Next
' oTbl.ConvertToText
Else
End If
End With
ErrExit:
Application.ScreenUpdating = True
End Sub
Sub FormatRows(oTbl As Table, x As Long, Hght As Single)
With oTbl
With .Rows(x)
.Height = Hght
.HeightRule = wdRowHeightExactly
.Range.Style = "TblPic"
.Cells.VerticalAlignment = wdCellAlignVerticalCenter
End With
With .Rows(x + 1)
.Height = CentimetersToPoints(0.5)
.HeightRule = wdRowHeightExactly
.Range.Style = "Normal"
End With
End With
End Sub
Last edited by macropod; 03-05-2022 at 07:06 PM. Reason: Split thread & delete duplicate |
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#2
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The code requires multiple changes for that. Try:
Code:
Sub AddPics()
Application.ScreenUpdating = False
Dim Stl As Style, i As Long, j As Long, c As Long, r As Long, NumCols As Long, iShp As InlineShape
Dim oTbl As Table, TblWdth As Single, StrTxt As String, RwHght As Single, ColWdth As Single
On Error GoTo ErrExit
NumCols = 1 'CLng(InputBox("Cuantas columnas por fila?"))
RwHght = CentimetersToPoints(8) '(CSng(InputBox("¿Altura maxima de la fila?")))
On Error GoTo 0
'Selecciona e inserta fotos
With Application.FileDialog(msoFileDialogFilePicker)
.Title = "Seleccion de imagenes y click en Abrir"
.Filters.Add "Imagenes", "*.gif; *.jpg; *.jpeg; *.bmp; *.tif; *.png"
.FilterIndex = 2
If .Show = -1 Then
'Crea un Estilo de parrafo con 0 espacios antes/despues y alineado al centro.
With ActiveDocument
On Error Resume Next
Set Stl = .Styles("TblPic")
If Stl Is Nothing Then Set Stl = .Styles.Add(Name:="TblPic", Type:=wdStyleTypeParagraph)
On Error GoTo 0
With .Styles("TblPic").ParagraphFormat
.Alignment = wdAlignParagraphCenter
.KeepWithNext = True
.SpaceAfter = 0
.SpaceBefore = 0
End With
.Styles(wdStyleNormal).ParagraphFormat.SpaceBefore = 0
End With
'Agregue una tabla de 2 filas por NumCols-column para colocar las imágenes
Set oTbl = Selection.Tables.Add(Range:=Selection.Range, NumRows:=3, NumColumns:=NumCols)
With ActiveDocument.PageSetup
TblWdth = .PageWidth - .LeftMargin - .RightMargin - .Gutter
ColWdth = CentimetersToPoints(15) 'TblWdth / NumCols
End With
With oTbl
.AutoFitBehavior (wdAutoFitFixed)
.TopPadding = 0
.BottomPadding = 0
.LeftPadding = 0
.RightPadding = 0
.Spacing = 0
.Columns.Width = ColWdth
.Borders.Enable = True
'.Spacing = 9
End With
CaptionLabels.Add Name:="Fotografía nº"
For i = 1 To .SelectedItems.Count Step NumCols
r = ((i - 1) / NumCols + 1) * 3 - 2
'Formato de filas
Call FormatRows(oTbl, r, RwHght)
For c = 1 To NumCols
j = j + 1
'Inserta la foto
Set iShp = ActiveDocument.InlineShapes.AddPicture( _
FileName:=.SelectedItems(j), LinkToFile:=False, _
SaveWithDocument:=True, Range:=oTbl.Cell(r, c).Range)
With iShp
.LockAspectRatio = True
If (.Width < ColWdth) And (.Height < RwHght) Then
.Width = ColWdth
If .Height > RwHght Then .Height = RwHght
End If
End With
'Obtener el nombre de la imagen para el pie de foto
StrTxt = Split(.SelectedItems(j), "\")(UBound(Split(.SelectedItems(j), "\")))
StrTxt = ": " & Split(StrTxt, ".")(0)
'Inserta el título Caption en la fila debajo de la imagen
With oTbl
With .Cell(r + 1, c)
.Borders(wdBorderLeft).Visible = False
.Borders(wdBorderRight).Visible = False
End With
With .Cell(r + 2, c).Range
.InsertBefore vbCr
.Characters.First.InsertCaption Label:="Fotografía nº", Title:=StrTxt, _
Position:=wdCaptionPositionBelow, ExcludeLabel:=False
.Characters.First = vbNullString
.Characters.Last.Previous = vbNullString
End With
End With
'Salir cuando hayamos terminado
If j = .SelectedItems.Count Then Exit For
Next
'Agregue filas adicionales según sea necesario
If j < .SelectedItems.Count Then
oTbl.Rows.Add
oTbl.Rows.Add
oTbl.Rows.Add
End If
Next
' oTbl.ConvertToText
With oTbl
For r = .Rows.Count - 2 To 3 Step -3
.Split .Rows(r)
Next
End With
Else
End If
End With
ErrExit:
Application.ScreenUpdating = True
End Sub
Sub FormatRows(oTbl As Table, x As Long, Hght As Single)
With oTbl
With .Rows(x)
.Height = Hght
.HeightRule = wdRowHeightExactly
.Range.Style = "TblPic"
.Cells.VerticalAlignment = wdCellAlignVerticalCenter
End With
With .Rows(x + 1)
.Height = CentimetersToPoints(0.5)
.HeightRule = wdRowHeightExactly
.Range.Style = wdStyleNormal
End With
With .Rows(x + 2)
.Height = CentimetersToPoints(0.5)
.HeightRule = wdRowHeightExactly
.Range.Style = wdStyleNormal
.Cells.VerticalAlignment = wdCellAlignVerticalCenter
End With
End With
End Sub
__________________
Cheers, Paul Edstein [Fmr MS MVP - Word] |
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#3
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WOW, It works perfect. Thanks a lot.
Could you explain to me what these lines of code do? I execute it step by step and still I don't understand it very well: Code:
With oTbl
For r = .Rows.Count - 2 To 3 Step -3
.Split .Rows(r)
Next
End With
Code:
For i = 1 To .SelectedItems.Count Step NumCols
r = ((i - 1) / NumCols + 1) * 3 - 2
MsgBox r
Last edited by gorkac; 03-06-2022 at 12:44 AM. Reason: One more question. |
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#4
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One last question please.
Bold this part of the only: Code:
CaptionLabels.Add Name:="Fotografía nº"
For i = 1 To .SelectedItems.Count Step NumCols
r = ((i - 1) / NumCols + 1) * 3 - 2
'Formato de filas
Call FormatRows(oTbl, r, RwHght)
For c = 1 To NumCols
j = j + 1
'Inserta la foto
Set iShp = ActiveDocument.InlineShapes.AddPicture( _
FileName:=.SelectedItems(j), LinkToFile:=False, _
SaveWithDocument:=True, Range:=oTbl.Cell(r, c).Range)
With iShp
.LockAspectRatio = True
If (.Width < ColWdth) And (.Height < RwHght) Then
.Width = ColWdth
If .Height > RwHght Then .Height = RwHght
End If
End With
'Obtener el nombre de la imagen para el pie de foto
StrTxt = Split(.SelectedItems(j), "\")(UBound(Split(.SelectedItems(j), "\")))
StrTxt = ": " & Split(StrTxt, ".")(0)
"Fotografía nº 1: xxxxx" "Fotografía nº 2: xxxxx" "Fotografía nº 3: xxxxx" and so |
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#5
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Quote:
Code:
.Split .Rows(r) 2. The line: Code:
r = ((i - 1) / NumCols + 1) * 3 - 2 Quote:
Code:
.Characters.Last.Previous = vbNullString Code:
.Collapse wdCollapseStart
.MoveEndUntil ":"
.End = .End + 1
.Style = wdStyleStrong
__________________
Cheers, Paul Edstein [Fmr MS MVP - Word] |
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#6
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It works perfect, THANKS ¡¡¡¡
One last request, how do I make more space where I indicate with the arrow? Screenshot_20220307-120413_Samsung Internet Beta.jpg Last edited by gorkac; 03-07-2022 at 04:41 AM. Reason: One more question. |
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#7
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After:
Code:
.Split .Rows(r) Code:
.Range.Characters.Last.Next.ParagraphFormat.SpaceAfter = 18
__________________
Cheers, Paul Edstein [Fmr MS MVP - Word] |
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#8
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Yes, its, certain.
One last thing, since the work is perfect and I don't bother you anymore. Is it possible to change the style of the second row? Captura.PNG |
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#9
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It would have been helpful had you specified all requirements up front.
Replace: Code:
With oTbl
For r = .Rows.Count - 2 To 3 Step -3
.Split .Rows(r)
.Range.Characters.Last.Next.ParagraphFormat.SpaceAfter = 18
Next
End With
Code:
With oTbl
For r = .Rows.Count To 1 Step -3
With .Rows(.Rows.Count).Borders
.OutsideLineStyle = wdLineStyleDouble
.OutsideColorIndex = wdGreen
End With
If .Rows.Count > 3 Then .Split .Rows(r - 2)
.Range.Characters.Last.Next.ParagraphFormat.SpaceAfter = 18
Next
End With
__________________
Cheers, Paul Edstein [Fmr MS MVP - Word] |
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#10
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I don't know how to thank you for your help. Requests are improvements that occur to me.
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| Tags |
| solved |
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