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The lines you want can probably be found using a wildcard Find, something along the lines of:
Find = <[0-9]{4,6}[!^13]{4,} but we'd probably need more of a description of what the lines to be found contain than what you've provided so far. In your example: 150710000XXX CORP NAME, LLC I can understand what the first six digits (150710) represent, but then you have a further three 0s followed by what I suppose are just three random alpha characters followed by what appears to be just a single space before the corporation name. After the date, are there always three digits followed by three alpha characters, all as an unbroken string? Are there actually three spaces before the corporation name, or just those three alpha characters?
__________________
Cheers, Paul Edstein [Fmr MS MVP - Word] |
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| Tags |
| excel 2013, extract word to excel, word 2013 |
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