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Hi redzan,
Apart from the ###, which you haven't told us anything about, this can be done without a macro, using a wildcard Find/Replace, where: Find = STUDY: ([!^13]{1,})*: ([!^13]{1,})*: ([!^13]{1,})*: ([!^13]{1,})*: ([!^13]{1,})*: ([!^13]{1,}) Replace = \1,\2,\3,\4,\5,\6 Assuming you have multiple records of 6 fields each, each set will be in a new paragraph.
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Cheers, Paul Edstein [Fmr MS MVP - Word] |
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