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#1
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Hi,
I'm trying to use this formula Quote:
I get a "N/A" error. Can someone tell me where I went wrong? I'm not a formula person. But, trying to help a friend Charles https://www.excelforum.com/newthread...postthread&f=8 Last edited by charlesdh; 04-12-2017 at 06:11 PM. Reason: Posted to another site |
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#2
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An average that includes "" as a number ain't going nowhere.
PS: Your link doesn't work.
__________________
Cheers, Paul Edstein [Fmr MS MVP - Word] |
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#3
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Sorry. The thread I posed was incorrect.
Here's the link. https://www.excelforum.com/excel-for...-show-n-a.html I reposted to get the link and am getting some help. But, still no answer. Any help would be thankful. Attached is a copy of my workbook. Charles |
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#4
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Maybe like the attached.
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#5
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xor,
Thanks for your help. I modified your formula. The reason is if I changed the date from 2017 to 2016 I received a "Divide by 0" error. Code:
AVERAGEIF('Weekly Stats Data '!A15:A45,L6-1,WeeklyStats[SUITABILITY RATE])
''changed to
AVERAGEIF('Weekly Stats Data '!A15:A45,L6,WeeklyStats[SUITABILITY RATE])
Can always depend on help from this forum. Charles https://www.excelforum.com/excel-for...-show-n-a.html Last edited by charlesdh; 04-21-2017 at 11:30 AM. Reason: added url for help I received. |
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#6
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I wrote L6-1 because the header in the column where I entered the formula says 2016 Average and L6-1 = 2016.
I must be misunderstanding something. |
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#7
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Thanks, It was my error.
Thanks for your help. Charles |
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