Copying part of a cell to a new cell

Catalin.B · #1 01-27-2012, 09:41 AM

Quote:

Originally Posted by paulw793

Is there anyway to add onto the second formula to only copy digits and not characters?

To extract numbers from text, best is to use a macro, like this:
(can be set to extract decimal, and/or negative numbres, with the optional arguments:

Code:

Function ExtrageNumar(rCell As Range, _
     Optional CuZecimale As Boolean, Optional Negative As Boolean) As Double


Dim iCount As Integer, i As Integer, iLoop As Integer
Dim sText As String, strNeg As String, strDec As String
Dim lNum As String
Dim vVal, vVal2
    
    sText = rCell
    If CuZecimale = True And Negative = True Then
        strNeg = "-"
        strDec = ","
    ElseIf CuZecimale = True And Negative = False Then
        strNeg = vbNullString
        strDec = ","
    ElseIf CuZecimale = False And Negative = True Then
        strNeg = "-"
        strDec = vbNullString
    End If

    iLoop = Len(sText)
            For iCount = iLoop To 1 Step -1
                vVal = Mid(sText, iCount, 1)
                If IsNumeric(vVal) Or vVal = strNeg Or vVal = strDec Then
                    i = i + 1
                    lNum = Mid(sText, iCount, 1) & lNum
                        If IsNumeric(lNum) Then
                            If CDbl(lNum) < 0 Then Exit For
                        Else
                          lNum = Replace(lNum, Left(lNum, 1), "", , 1)
                        End If
                End If
                If i = 1 And lNum <> vbNullString Then lNum = CDbl(Mid(lNum, 1, 1))
            Next iCount

    ExtrageNumar = CDbl(lNum)

End Function

Then, in cell, use : =ExtrageNumar(E8;1;1) (second and third arguments are optional, and are used for negative and decimals)
note:
the code may need to be modified according to your regional settings:
on lines 13 and 16, strDec = "," is strDec = "." if this is your regional decimal delimiter

paulw793 · #2 01-27-2012, 10:46 AM

Thanks Catilan! I got it all figured out!

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