Well, apart from the fact you deleted an existing expression in that macro, you added a space to the start of the new Find expression, omitted a new Replace expression, which means the preceding character would be deleted and a paragraph inserted in its place and, by putting it after the code that applies the 'Strong' Style, would turn the replaced output bold. Try:
Code:
Sub Demo()
Application.ScreenUpdating = False
With ActiveDocument.Range
With .Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchWildcards = True
.Text = "([!1-9])[0]{1,}([0-9]{1,})"
.Replacement.Text = "\1\2"
.Execute Replace:=wdReplaceAll
End With
End With
Application.ScreenUpdating = True
End Sub
or, to integrate it into yesterday's macro:
Code:
Sub Demo()
Application.ScreenUpdating = False
With ActiveDocument.Range
.InsertBefore " "
With .Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindContinue
.Format = False
.MatchWildcards = True
.Text = "([!1-9])[0]{1,}([0-9]{1,})"
.Replacement.Text = "\1\2"
.Execute Replace:=wdReplaceAll
.Text = ".([0-9]{1,3}.)"
.Replacement.Text = ". \1"
.Execute Replace:=wdReplaceAll
.Text = " ([a-e].)"
.Replacement.Text = "^p\1"
.Execute Replace:=wdReplaceAll
.Replacement.Style = "Strong"
.Text = " ([0-9]{1,3}.)"
.Execute Replace:=wdReplaceAll
End With
.Characters.First.Delete
End With
Application.ScreenUpdating = True
End Sub
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