Replacing carriage return with line return in specific string



I have a large document with a number of clauses which start

Clause XX (carriage return)
Title of Clause

And I want it replaced with

Clause XX (Line return)
Title of Clause

where XX is the number of the clause - currently running from 1 to 130 but can vary in different documents

What i have tried so far is using the replace command, selecting more \nd ticking use wild cards. I have then used the following which i thought would work

Find What: Article ([0-9])(^13)
Replace with: \1 (^10)

Where I believe ^13 is Carriage return and ^10 is Line break.

The reason for doing this is that I want to reformat all there Clause Titles as Style Heading 2 so I can use them in a Table of Contents with both Parts appearing as one entry as opposed to two separate entries because of the Carriage Returns...

NOTE: it is important that the Article XX is followed by a Carriage return (or space and Carriage Return) because the Clauses are also refereed to within the text, and I dont want to replace them.

Any assistance in getting this to work most welcome.

PS: sorry but I dont want to do this with a macro.
Thanks
GreenBoy

Find
(Clause [0-9]{1,})^13
Replace with
\1^11
not
\1 (^10)
with the wildcard option set http://www.gmayor.com/replace_using_wildcards.htm

__________________
Graham Mayor - MS MVP (Word) (2002-2019)
Visit my web site for more programming tips and ready made processes www.gmayor.com

Thank you Graham - this works like a charm.

Also thanks for the link to your page.

One follow-up question if I may, it turns out the document I have isnt consistent on the Article titles and has between zero and 2 spaces after the article number and the Paragraph mark. eg:

Article 1^13
Article 2 ^13
Article 3 ^13

Is there a way to remove these as well?
I probably should be able to solve this, but after a night up wrestling with the rest of the document its a little beyond me at the moment.

Thanks again
GreenBoy