I have a document of several hundred pages, much of it lists in laid out in paragraphs. Each item is separated by a ";". This was scanned via OCR software and many times there is no space between the ; and the next item.

I want to use the replace all feature to locate all instances where this lack of a space is and then insert a space.



I have figured out what to type in the 'find' field and that is ";[! ]" however, I do not know how to get it to simply put a space after the semicolon but before the next letter. What syntax, if any can I use to do this in the 'replace with' field?

Using a wildcard Find Replace:
Find = ;([! ^13^l])
Replace = ; \1
The addition of ^13^l to the Find expression ensures the F/R doesn't put the space in at the end of lines terminated by a paragraph break or line break.

__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]