Hi,



I am trying the following find and replace in Word 2016 with Wildcards on:

(p.)([1-9])
\1 \2

The author has, for instance, p.23 and I want it to be p. 23 (with a space between the abbreviation for page and the numeral).

However, my output is p.2 3

I'm guessing I'm just missing a simple fix, but I'm not seeing it at the moment. Any ideas? Thank you in advance!

A wildcard Find/Replace, with:
Find = (p.)([0-9])
Replace = \1 \2
should turn:
p.23
into:
p. 23
I can see no reason for the behaviour you describe with that F/R. I suspect an errant F/R has been used somewhere along the line.

__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]

Yea, I just wanted to make sure I wasn't going crazy. I just repeated it and got the same issue. I do have some tracked changes in the document (although it's not too heavy yet). There only ended up being a few instances in the document, so I just changed them manually. If I run into this again in the future, I'll see if I can nail down the problem. Thank you for your quick response Paul.

Ah, using Tracked Changes changes everything! That explains the behaviour. You may get better results with:
Find = (p.)([0-9]{1,})
Replace = \1 \2
but you may even need to turn Tracked Changes off while doing the F/R.

__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]