As you can see in this image: http://i.gyazo.com/8996a86cf19862e36838e56c3ebcc6c2.png



I want to delete all the text at the left of "lbs" and the word lbs as well, leaving only the (amount kg)

In case it's possible, I want to eliminate the parentesis, leaving only the "amount kg"

It's a really long list, so I just want to do it by replacing, but I don't know how to do it.

Thank you.

You can do that with a wildcard Find/Replace, where;
Find = [!^13]@([0-9.]@ kg)*^13
Replace = \1^p

__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]

I find myself once again puzzled by a wildcard search.
As I read your Find terms, you're telling Word to not find one or more hard returns followed by a term, designated by parentheses, comprising one or more numerals followed by a period and a space, which term is then followed by another space and then kg. This is then followed by any number of other characters and then a hard return.

My questions, if you would be so kind, are:
1. Is the return avoidance at the beginning actually another way of saying "1 or more of any characters (except that)? Is this used because, say, [?!^13]@ would not for some reason?
2. Why the two spaces after the number of kgs?
3. Why the asterisk after kg? Is this to eliminate the close peren?

Thanks.

Breaking down the expression:
• [!^13] represents any character other than a paragraph break, so [!^13]@ says to find a sequence of such characters.
• ([0-9. ]@ kg) says to find & store any sequence of 0-9 and /or a period followed by ' kg'. The parens in the expression do not represent the parens in the text - they're the std wildcard expression for storing a string.
• there are no "spaces after the number of kgs"
• the *^13 after kg) says to find any number of characters after the 'kg' until a paragraph break is found.

__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]

Thank you for clarifying. One thing I learned from this is that the use of the backslash and a number in the replacement field refers only to a terms defined by being enclosed in parentheses, which is why \1 in this expression ignores anything before the open paren.

I am still not entirely clear, however, about the use of spaces, which I didn't state clearly enough. Your expression has a space between the period and the close bracket, and one between the @ and kg. A special wildcard lookup table I have suggests that these may be necessary to separate items in an expression, but that if a space needed to be indicated, ^w would have to be used. Is this correct?

Thank you, sir.

That was an error in the posted expression, which I've now fixed.
No, if you need to indicate an space, as distinct from any whitespace (which includes tabs & non-breaking spaces), you'd insert an actual space as I have done. In any event, ^w isn't valid in a wildcard Find expression so, if you wanted to capture all whitespace characters, you'd have to specifically add each one to the expression (e.g. [ ^0160^t]).

__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]