#1
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Is there a way remove periods at the end of every bullet in a document?
Hello,
I have a document that is a couple hundred pages long, and the writer put periods at the end of every bullet: http://imgur.com/waos6vx What I want is this - periods removed at the end of every bullet (If the last character is a period, remove it): http://imgur.com/CXxVahb Is there a way to remove periods at the end of every bullet (or specific styles) throughout the document that does not require a macro? I do not have the knowledge to program such a thing. Could Find & Replace somehow be used? |
#2
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Assuming your document is properly formatted with paragraph Styles, such that the bulleted paragraphs use different Styles than the non-bulleted ones, this can be done with a few Find/Replace operations, where:
Find = .^p Replace = ^p and you specify the relevant paragraph style as a Find parameter. If you use 'replace all', you might want to follow that up with a spell-check to ensure periods attached to abbreviations such as etc. get restored (I note there is one in your sample).
__________________
Cheers, Paul Edstein [Fmr MS MVP - Word] |
#3
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Ohoho, thanks Macropod. That works great. Yeah, I'll check for words like "etc" afterwards to put the periods back in, but this is a good timesaver.
EDIT: If anyone else is looking at Macropod's method, if you have any bullets that have a space after the period or a section break (instead of a paragraph end), those periods will not be picked up by the .^p find/replace. So, do a final manual Find check afterwards, to catch any stragglers. |
#4
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You really shouldn't have spaces, tabs, etc. before a paragraph break or a section break. You can clear out those spaces & tabs with a wildcard Find/Replace, where:
Find = [^t ]@([^13^12]) Replace = \1 You should generally also have paragraph breaks before Section breaks. You can ensure that with a wildcard Find/Replace, where: Find = ([!^13])([^12]) Replace = \1^p\2
__________________
Cheers, Paul Edstein [Fmr MS MVP - Word] |
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