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#1
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I had help from Vivka putting this code together but I've since updated the code so it will only run if text has been selected within the document. In the test document attached, I want to select all the text from 1 CABINET SUB-COMMITTEES down to clause 3.12 but I'm getting a run time error 91 occur. I've tested the code and if I select the text from 1 CABINET SUB-COMMITTEES down to 3.10. the code works, also if I select clauses 3.11 and 3.12 only the code works so I'm not sure why it errors out selecting all the text from manual clause 1 down to 3.12. Can anyone help at all.
This part of the code is where it errors Code:
'Delete all periods immediately before a tab: While rng.Characters.Last.Previous = "." Code:
Sub FormatManualNumbering() Dim rng As Range Dim rngEnd As Long Dim i As Paragraph, N As Long Application.ScreenUpdating = False 'Call DeleteEmptyParas 'Call DPU_RemoveFirstLineIndents If Selection.Type = wdSelectionIP Then MsgBox Prompt:="You have not selected any text!" Exit Sub End If With Selection.Range Set rng = Selection.Range With rng 'Removes any indents at beginning of paragraphs For Each i In Selection.Paragraphs 'cycling in the pragraphs of the active document For N = 1 To i.Range.Characters.count If i.Range.Characters(1).text = " " Or i.Range.Characters(1).text = "Char(32) " Or i.Range.Characters(1).text = "Char(32)\( " Or i.Range.Characters(1).text = Chr(9) Or i.Range.Characters(1).text = Chr(160) Or i.Range.Characters(1).text = Chr(40) Then i.Range.Characters(1).Delete Else: Exit For End If Next N Next End With With Selection.Range Set rng = Selection.Range With rng.Find 'Remove space before brackets first line indent .ClearFormatting .Replacement.ClearFormatting .text = "^13 (" .Replacement.text = "^p(" .Execute Replace:=wdReplaceAll End With With Selection.Range Set rng = Selection.Range rngEnd = rng.End Selection.Range.InsertBefore vbCr With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = False .MatchWildcards = False 'Remove spaces starting paras: .text = "^p^w" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Remove spaces before para signs: .text = "^w^p" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Remove empty paras: .MatchWildcards = True .text = "^13{2,}" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Insert a tab before any 1st letter in a para: .text = "(^13[!^13]@)([A-Za-z])" .Replacement.text = "\1^t\2" .Execute Replace:=wdReplaceAll 'Replace two tabs with one tab: .text = "^t^t" .Replacement.text = "^t" .Execute Replace:=wdReplaceAll 'Delete tabs between letters, which have been inserted using 'the code to insert a tab before any 1st letter in a para previously: .text = "([A-Za-z])^t([A-Za-z])" .Replacement.text = "\1\2" .Execute Replace:=wdReplaceAll End With With Selection.Range Set rng = Selection.Range Do With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = True .MatchWildcards = True 'Find a str between a tab & the nearest previous para sign, i.e. 'a str between a para sign & a tab, excluding other paras in-between: .text = "^13[!^13]@^t" If .Execute And rng.End <= rngEnd Then .text = "[,:; ]" .Replacement.text = "." .Execute Replace:=wdReplaceAll Else: Exit Do End If 'Delete all periods immediately before a tab: While rng.Characters.Last.Previous = "." rng.Characters.Last.Previous.Delete Wend rng.Collapse wdCollapseEnd End With Loop 'Reset rng (see the comment above): With Selection.Range Set rng = Selection.Range With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = True .MatchWildcards = True 'Insert periods after lone 1st-level numberings: .text = "(^13[0-9]{1,})^t" .Replacement.text = "\1.^t" .Execute Replace:=wdReplaceAll 'Delete extra periods in the doc: .text = "[.]{2,}" .Replacement.text = "." .Execute Replace:=wdReplaceAll 'Delete tab after opening bracket: .text = "(^13[(])^t" .Replacement.text = "\1" .Execute Replace:=wdReplaceAll 'Delete tab after opening double quote (Chr(34) & Chr(147)) after para marks: .text = "(^13" & "[" & Chr(34) & Chr(147) & "]" & ")^t" .Replacement.text = "\1" .Execute Replace:=wdReplaceAll End With 'Delete the doc's starting para sign inserted previously: Selection.Range.Characters.First.Delete Application.ScreenUpdating = True MsgBox "Complete" End With End With End With End With End With Set rng = Nothing End Sub |
#2
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you are iterating over a list that's changing.
how about Replacing dot-tab with just tab until there's none left? |
#3
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Hi, Shelley Lou! 1) Your code works without a hitch (no errors returned) on my machine,
2) There were some duplicate / redundant code lines in your code, so after fine-tuning the code (I hope, I really did it) it may look as follows: Code:
Sub FormatManualNumbering() Dim rng As range Dim rngEnd As Long Application.ScreenUpdating = False If selection.Type = wdSelectionIP Then MsgBox Prompt:="You have not selected any text!" Exit Sub End If Set rng = selection.range rngEnd = rng.End selection.range.InsertBefore vbCr With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = False .MatchWildcards = False 'Remove spaces starting paras: .text = "^p^w" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Remove spaces before para signs: .text = "^w^p" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Remove empty paras: .MatchWildcards = True .text = "^13{2,}" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Insert a tab before any 1st letter in a para: .text = "(^13[!^13]@)([A-Za-z])" .Replacement.text = "\1^t\2" .Execute Replace:=wdReplaceAll 'Replace two tabs with one tab: .text = "^t^t" .Replacement.text = "^t" .Execute Replace:=wdReplaceAll 'Delete tabs between letters, which have been inserted using 'the code to insert a tab before any 1st letter in a para previously: .text = "([A-Za-z])^t([A-Za-z])" .Replacement.text = "\1\2" .Execute Replace:=wdReplaceAll End With Set rng = selection.range Do With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = True .MatchWildcards = True 'Find a str between a tab & the nearest previous para sign, i.e. 'a str between a para sign & a tab, excluding other paras in-between: .text = "^13[!^13]@^t" If .Execute And rng.End <= rngEnd Then .text = "[,:; ]" .Replacement.text = "." .Execute Replace:=wdReplaceAll Else: Exit Do End If 'Delete all periods immediately before a tab: While rng.Characters.Last.Previous = "." rng.Characters.Last.Previous.Delete Wend rng.Collapse wdCollapseEnd End With Loop 'Reset rng (see the comment above): Set rng = selection.range With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = True .MatchWildcards = True 'Insert periods after lone 1st-level numberings: .text = "(^13[0-9]{1,})^t" .Replacement.text = "\1.^t" .Execute Replace:=wdReplaceAll 'Delete extra periods in the doc: .text = "[.]{2,}" .Replacement.text = "." .Execute Replace:=wdReplaceAll 'Delete tab after opening bracket: .text = "(^13[(])^t" .Replacement.text = "\1" .Execute Replace:=wdReplaceAll 'Delete tab after opening double quote (Chr(34) & Chr(147)) after para marks: .text = "(^13" & "[" & Chr(34) & Chr(147) & "]" & ")^t" .Replacement.text = "\1" .Execute Replace:=wdReplaceAll End With 'Delete the doc's starting para sign inserted previously: selection.range.Characters.First.Delete Application.ScreenUpdating = True MsgBox "Complete" Set rng = Nothing End Sub |
#4
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Hello again Vivka, how strange that it works on your PC, I've just run your updated code but still getting the run time error 91 on this line
Code:
While rng.Characters.Last.Previous = "." |
#5
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Hi, Shelley Lou!
Hopefully, you'll like the following. Code:
Sub FormatManualNumbering() Dim rng As range Dim rngEnd As Long Application.ScreenUpdating = False If selection.Type = wdSelectionIP Then MsgBox Prompt:="You have not selected any text!" Exit Sub End If Set rng = selection.range rng.InsertBefore vbCr rngEnd = selection.End With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = False .MatchWildcards = False 'Remove spaces starting paras: .text = "^p^w" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Remove spaces before para signs: .text = "^w^p" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Remove empty paras: .MatchWildcards = True .text = "^13{2;}" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Insert a tab before any 1st letter in a para: .text = "(^13[!^13]@)([A-Za-z])" .Replacement.text = "\1^t\2" .Execute Replace:=wdReplaceAll 'Replace two tabs with one tab: .text = "^t^t" .Replacement.text = "^t" .Execute Replace:=wdReplaceAll 'Delete tabs between letters, which have been inserted using 'the code to insert a tab before any 1st letter in a para previously: .text = "([A-Za-z])^t([A-Za-z])" .Replacement.text = "\1\2" .Execute Replace:=wdReplaceAll End With rng.Select Set rng = selection.range Do With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = True .MatchWildcards = True 'Find a str between a tab & the nearest previous para sign, i.e. 'a str between a para sign & a tab, excluding other paras in-between: .text = "^13[!^13]@^t" If .Execute And rng.End <= rngEnd Then .text = "[,:; ]" .Replacement.text = "." .Execute Replace:=wdReplaceAll Else: Exit Do End If 'Delete all periods immediately before a tab: While rng.Characters.Last.Previous = "." rng.Characters.Last.Previous.Delete Wend rng.Collapse wdCollapseEnd End With Loop Set rng = selection.range With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = True .MatchWildcards = True 'Insert periods after lone 1st-level numberings: .text = "(^13[0-9]{1;})^t" .Replacement.text = "\1.^t" .Execute Replace:=wdReplaceAll 'Delete extra periods in the doc: .text = "[.]{2;}" .Replacement.text = "." .Execute Replace:=wdReplaceAll 'Delete tab after opening bracket: .text = "(^13[(])^t" .Replacement.text = "\1" .Execute Replace:=wdReplaceAll 'Delete tab after opening double quote (Chr(34) & Chr(147)) after para marks: .text = "(^13" & "[" & Chr(34) & Chr(147) & "]" & ")^t" .Replacement.text = "\1" .Execute Replace:=wdReplaceAll End With 'Delete the doc's starting para sign inserted previously: selection.range.Characters.First.Delete Application.ScreenUpdating = True MsgBox "Complete" Set rng = Nothing End Sub |
#6
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Hi Vivka, thank you for the updated code, unfortunately I'm still getting the error 91 when I select all the text in the test document so I'm a bit baffled to say the least as it seems you are running the code without any errors. If I only select text down to the last few paragraphs it works bizarrely. I will keep trying to get it right.
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#7
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Hu, Shelley Lou! I tested the code only on plain text (and it worked perfectly), not on tables. You initially asked for a code to work on manual list numberings, but your sample document has tables with automatic numberings, that's why .text = "^13[!^13]@^t" makes wrong finds, which causes the error.
Please, try this version: Code:
Sub FormatManualNumbering() Dim rng As range Dim rngEnd As Long Application.ScreenUpdating = False If selection.Type = wdSelectionIP Then MsgBox Prompt:="You have not selected any text!" Exit Sub End If Set rng = selection.range rng.InsertBefore vbCr rngEnd = selection.End With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = False .MatchWildcards = False 'Remove spaces starting paras: .text = "^p^w" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Remove spaces before para signs: .text = "^w^p" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Remove empty paras: .MatchWildcards = True .text = "^13{2,}" .Replacement.text = "^p" .Execute Replace:=wdReplaceAll 'Insert a tab before any 1st letter in a para: .text = "(^13[!^13]@)([A-Za-z])" .Replacement.text = "\1^t\2" .Execute Replace:=wdReplaceAll 'Replace two tabs with one tab: .text = "^t^t" .Replacement.text = "^t" .Execute Replace:=wdReplaceAll 'Delete tabs between letters, which have been inserted using 'the code to insert a tab before any 1st letter in a para previously: .text = "([A-Za-z])^t([A-Za-z])" .Replacement.text = "\1\2" .Execute Replace:=wdReplaceAll End With rng.Select Set rng = selection.range Do With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = True .MatchWildcards = True 'Find a str between a tab & the nearest previous para sign, i.e. 'a str between a para sign & a tab, excluding other paras in-between: .text = "^13[!^13]@^t" 'Skip tables: If .Execute And rng.Information(wdWithInTable) = False And rng.End <= rngEnd Then .text = "[,:; ]" .Replacement.text = "." .Execute Replace:=wdReplaceAll Else: Exit Do End If rng.Collapse wdCollapseEnd End With Loop Set rng = selection.range With rng.Find .ClearFormatting .Replacement.ClearFormatting .Forward = True .Wrap = wdFindStop .Format = True .MatchWildcards = True 'Delete all periods immediately before a tab: .text = "[.]{1,}^t" .Replacement.text = "^t" .Execute Replace:=wdReplaceAll 'Insert periods after lone 1st-level numberings: .text = "(^13[0-9]{1,})^t" .Replacement.text = "\1.^t" .Execute Replace:=wdReplaceAll 'Delete extra periods in the doc: .text = "[.]{2,}" .Replacement.text = "." .Execute Replace:=wdReplaceAll 'Delete tab after opening bracket: .text = "(^13[(])^t" .Replacement.text = "\1" .Execute Replace:=wdReplaceAll 'Delete tab after opening double quote (Chr(34) & Chr(147)) after para marks: .text = "(^13" & "[" & Chr(34) & Chr(147) & "]" & ")^t" .Replacement.text = "\1" .Execute Replace:=wdReplaceAll End With 'Delete the doc's starting para sign inserted previously: selection.range.Characters.First.Delete Application.ScreenUpdating = True MsgBox "Complete" Set rng = Nothing End Sub Last edited by vivka; 09-25-2024 at 11:40 PM. |
#8
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Hi Vivka, the code should only run on text that is selected i.e. text selected directly after the table at clause 1.1 and before schedule 1, hopefully the way the code is written it should only work on selected text and nothing else in the document (the test document is how our leases are set up with tables and just for info purposes).
The idea was I was hoping the code only worked on selected text, if I copy and paste the text into a blank document (i.e. with no tables etc.) it does work, so I've gone back to that way to use the code and then once updated I copy it back into the lease document. Bit long winded but its how it will only work at the moment. Unfortunately when running your new code it ended up in an endless loop and I had to shut Word down. Thanks so much for all the help though, I really do appreciate it. |
#9
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The code from post #5 works like charm on any ranges but tables. I didn't see any issue. Very strange!
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#10
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Vivka, I wonder if its because you use semi colons and I have to use a comma e.g. {1;} to my {1,}, maybe that has something to do with it - long shot I know. I will close this thread now though as I don't think we can go any further with it now but thanks for all your help, always appreciated
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#11
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You are welcome, Shelley Lou! I'm sorry I couldn't help you!
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