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#1
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I would be really grateful for some pointers on where I'm going wrong with the below code. I have an array of words I want to change the space to a non breaking space between the word and digit(s) and their plural e.g looks for clause and clauses etc.
At the moment it is putting the non breaking space before the word e.g. clause. I've tried \1^s but that puts it at the end of the digit. I've tried \1^s\2 and other variations but they all just give me an error - I'm just not sure where I'm going wrong for something that should be quite straightforward. Code:
ArrFndB = Array("[Aa]ppendix", "[Cc]lause", "[Pp]aragraph", "[Pp]art", "[Ss]chedule") Code:
For i = 0 To UBound(ArrFndB) .text = "(" & ArrFndB(i) & "[s ]@[0-9.]{1,})" .Replacement.text = "^s\1" .Execute Replace:=wdReplaceAll Next |
#2
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The plural of appendix is not just adding an s to the end. It is normally appendixes or appendices. The problem you are having is that you are enclosing the find text in a single set of (brackets) when you need two separate sets if you want to replace something inside there.
This would all be a lot more straightforward if you simply expand the array to include all acceptable plurals. Code:
Dim arr() As String, i As Integer, sFind As String sFind = "[Aa]ppendix [Aa]ppendixes [Aa]ppendices [Cc]lause [Cc]lauses [Pp]aragraph [Pp]aragraphs [Pp]art [Pp]arts [Ss]chedule [Ss]chedules" arr = Split(sFind, " ") With ActiveDocument.Range.Find .ClearFormatting .Replacement.ClearFormatting .MatchWildcards = True For i = 0 To UBound(arr) .Text = "(" & arr(i) & ") ([0-9.]{1,})" .Replacement.Text = "\1^s\2" .Execute Replace:=wdReplaceAll Next End With
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Andrew Lockton Chrysalis Design, Melbourne Australia |
#3
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Hi, thank you so much, I can see where I was going wrong now, I've managed to replicate the code but in the opposite way i.e. find number then array for a different set of words so many thanks for pointing out where I was going wrong, much appreciated.
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