I have a Word document with interviewer questions and answers
The format is like this:
<Interviewer:><^t><One or more sentence(s) with closing punctuation><^p>
and I want an MS Word Find and Replace macro to convert each instance into this:
<bold><Interviewer:><space><Identical One or more sentence(s) with closing punctuation><^p></bold>

The macro routine would look something like this:

Sub Reformat_Tabbed_Para()
'
Selection.Find.ClearFormatting
Selection.Find.Replacement.ClearFormatting
Selection.Find.Replacement.Font.Bold = True
With Selection.Find


.Text = <><><><>
.Replacement.Text = "\1[space]\3\4"
.Forward = True
.Wrap = wdFindContinue
.Format = True
.MatchCase = False
.MatchWholeWord = False
.MatchAllWordForms = False
.MatchSoundsLike = False
.MatchWildcards = True
End With
Selection.Find.Execute Replace:=wdReplaceAll
End Sub

I believe there is code allowing me to find and replace the same string of characters and punctuation up to the ^p but cannot find the correct way of writing it.
Help would be much appreciated!

It is not apparent from your post whether you're working with HTML strings, or whether what you've posted is simply your attempt to represent the document content in HTML format.

__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]

My apologies, I thought that - since this is an MS Word VBA forum and I stated that I had a "Word document" and was looking for a solution using an "MS Word Find and Replace macro" - the expressions within chevrons would be understood to be the terms used in the F&R code given below.

In which case, you don't even need a macro - all you need is a single wildcard Find/Replace, where:
with the bold attribute applied to the replacement.

__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]

Thank you!
This - ([!^13]@^13) - is what I couldn't work out, was trying permutations involving (0-9A-z ) with 'ignore punctuation characters' specified, but it wasn't working.
Much appreciated!