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Old 01-02-2021, 05:47 AM
alex100 alex100 is offline Capture group in RegEx Windows 7 64bit Capture group in RegEx Office 2016
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Capture group in RegEx
 
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Default Capture group in RegEx

I am using the code below to find and replace some text. I uses a RegEx that has two groups "(.*?)".

Code:
Dim objRegex As regExp
Dim matches As MatchCollection
Dim fnd As Match
Set objRegex = New regExp
With objRegex


.Pattern = "\[\|\]" & vbCr & "(.*?)" & vbCr & "(.*?)" & "\|" & vbCr .Global = True .IgnoreCase = True Set matches = .Execute(Selection.Text) End With With Selection .HomeKey wdStory With .Find .ClearFormatting .Forward = True .Format = False .MatchCase = True For Each fnd In matches .Text = fnd .Execute If .Found = True Then Selection.TypeText Text:="-------------" End If Next fnd End With End With
The RegEx works good.

I do have a problem though... how can I capture the first group in the RegEx and add it before the replacement text (which is this line: "-------------")?

Currently, the replacement text is added using the 'Selection.TypeText' instruction, as you can see. That's because I couldn't find the way to use the '.Replacement.Text' instruction for this particular code. I tried using it, but nothing seemed to work.

Anyhow, I guess the solution could be something like this:

.Replacement.Text="$1-------------"

where $1 represents the first captured group in the RegEx. This is just an example that should help you better understand what I'm looking for.

Alex
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Old 01-02-2021, 02:39 PM
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macropod macropod is offline Capture group in RegEx Windows 10 Capture group in RegEx Office 2016
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If I understand your Regex correctly - and what you're trying to achieve - it's equivalent to a wildcard Find/Replace, where:
Find = \[\|\]^13[!^13]@^13[!^13]@\|^13
Replace = -------------^&
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