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#1
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My situation is this: I’ve got a table consisting of 2 columns and an unspecified number of rows. Though all cells in the second column have text, only some of the cells in the first columns have numbers. I need a way of quickly deleting whole rows, when the cell in the first column is empty, but leave the row if the cell in the first column is got a number in it. I imagin it could be as simple as a ‘for loop’ that loops the amount of times there are rows, followed by an ‘if statement’ –
For loop(i) if cell in column 1 == empty, remove row i + 1 The problem is I have no idea how to program using the VPA, and would really appreciate the help from someone who does 😊 Thank you in advance for any responses. What I'm trying to achive: -Before Sample Text Sample Text 1 Sample Text Sample Text 4 Sample Text -After 1 Sample Text 4 Sample Text It's worth noting the text at the bottom of the question doesn't appear in the table I expected it to, so just ignore the 'before' and 'after'. |
#2
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The basic code is as follows.
Code:
Sub wiperows() Dim i As Integer With Selection.Tables(1) For i = .Rows.Count To 1 Step -1 If Len(.Rows(i).Cells(1).Range.Text) = 2 Then .Rows(i).Delete Next i End With End Sub - the user hasn't put their cursor in the table before running the macro - there are vertically merged cells which confuses Word when it is looking for a 'row'
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Andrew Lockton Chrysalis Design, Melbourne Australia |
#3
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That's exactly what I was looking for! Thanks so much for taking the time and answering so quickly
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