![]() |
#1
|
|||
|
|||
![]()
I have some Shape Data rows setup on shape 1. One of those rows is Prop.Letter and it contains a fixed list of A;B;C;D. If I set Scratch.A1 to be =Prop.Letter, then Scratch.A1 shows the selected value (A, B, C, or D) as it should. If I put a formula in Scratch.B1 =IF(Scratch.A1="A",1,0), or =IF(Prop.Letter="A",1,0), Scratch.B1 always shows 1, even though the value of A1 is changing to either be A or something else. How can I correctly use the result of the Prop.Letter selection as a valid value in another cell's formula? I like playing with VBA, but I would prefer that this be a shapesheet formula as it will be a master which will be used in numerous projects.
|
#2
|
|||
|
|||
![]()
***Update: I just discovered the STRSAME() function and now it works the way I need it to. I don't really understand though why "A" on one cell does not equal "A" in another cell.
|
![]() |
Thread Tools | |
Display Modes | |
|
![]() |
||||
Thread | Thread Starter | Forum | Replies | Last Post |
Auto populate form (data from excel) in Word based on drop down list selection (data from excel) | wvlls | Word VBA | 1 | 03-22-2019 02:29 PM |
![]() |
Dudlee | Word VBA | 1 | 09-20-2016 04:58 PM |
![]() |
markharper80 | Excel | 3 | 02-16-2015 04:18 PM |
![]() |
omberlo | PowerPoint | 1 | 11-25-2012 06:44 AM |
![]() |
fedcco | Excel | 12 | 08-28-2012 10:43 PM |