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#4
01-25-2010, 02:09 PM
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Sorry, I meant that it expects every name in Columns A and B to have an equivalent in Columns D and E. So if, say, A36 has Kent and B36 has Clark, there should be a pair in D and E, on some row, with the same values.
Your description of the data indicates this is so, but I thought I should mention it explicitly. 
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