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#1
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![]() Right - I'll need a bit more info, please: Using your uploaded test sheet as an example - in the worksheet 'TECH ONLY' what exactly is it that you want to add up - can you tell me the exact column and word based on your workbook! Bird |
#2
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it's to only add up how many rows that column has something in it. so if there are 50 rows, and only say 20 has something in that column then the total would be 20.
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#3
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![]() Quote:
So you are only looking to count if there is ANYTHING in the row - OK Code:
=COUNTA(*RANGE*) COUNTA function will count all the cells and return the number that contain data Using the example sheet that you uploaded the PRW Only total box would contain the following formula if it were counting all the Sales Person column in the TECH ONLY worksheet: Code:
=COUNTA('TECH ONLY'!E5:E46) If you were looking for how many times the name Phil were to appear in the First Name column on the TECH ONLY worksheet... Code:
=COUNTIF('TECH ONLY'!C5:C46,"Phil") BTW - in PRW ONLY STATS cell F8 you should use a range operator, rather than individual cells when using =SUM - only when the cells are not next to each other do you need to revert to x+x+x+x ie. =SUM(B8:E8) is the same as =(B8+C8+D8+E8) in the second example you don't need SUM because you are using the + symbol which is what =SUM means! Welcome to the fun world of Excel formulas - just wait till BODMAS comes along to bite you - LOL! |
#4
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#5
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Hey BIRD, there's been another change in the plan. I wish my Supervisor would just make up their minds how they want this done, so that I can be done with it. So here's the problem
They want a formula that will total on which officer has pend in on cell and which officer has techs in another. example: officer joe has 12 tech and 20 pending officer john has 20 tech and 10 pending officer doe has 50 tech and 20 pending SHEET#1 colm #A will be officer name, colm #B will have the word tech or pend beside the officer row that the data is enter. On SHEET#2 the STATS will refect the total # of tech and a total # of pend for each officer. |
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