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Old 12-28-2011, 03:24 AM
ColinC ColinC is offline IF formula returns  TRUE  instead of evaluating  COUNTIF Windows 7 64bit IF formula returns  TRUE  instead of evaluating  COUNTIF Office 2010 64bit
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Default IF formula returns TRUE instead of evaluating COUNTIF

=IF((COUNTBLANK(A22:Y22))=0,"=COUNTIF(A22:Y22,">"& E22)","")



The above formula is intended to check whether a row (A22:Y22) is complete.
If all cells filled, return the number exceeding the reference cell E22.
If there are blank cells, return empty cell.
The above formula returns TRUE and does not evaluate the COUNTIF formula which works correctly in isolation.
Help please.
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  #2  
Old 12-28-2011, 05:02 AM
Catalin.B Catalin.B is offline IF formula returns  TRUE  instead of evaluating  COUNTIF Windows Vista IF formula returns  TRUE  instead of evaluating  COUNTIF Office 2010 32bit
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in the IF function, for Value if true, you should have
COUNTIF(A22:Y22,">"& E22) not
"=COUNTIF(A22:Y22,">"& E22)"
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Old 12-28-2011, 06:04 AM
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Pecoflyer Pecoflyer is offline IF formula returns  TRUE  instead of evaluating  COUNTIF Windows XP IF formula returns  TRUE  instead of evaluating  COUNTIF Office 2003
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Quote:
return the number exceeding the reference cell E22
What do you mean?
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Old 12-28-2011, 08:15 AM
ColinC ColinC is offline IF formula returns  TRUE  instead of evaluating  COUNTIF Windows 7 64bit IF formula returns  TRUE  instead of evaluating  COUNTIF Office 2010 64bit
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To PECOFLYER
Thankyou for your interest in my post. Sorry about the lack of clarity in the question. I meant in the range A22:Y22 return the number of cells with a value greater than the value in E22.
The problem has now been solved but thanks anyway.
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Old 12-28-2011, 08:21 AM
ColinC ColinC is offline IF formula returns  TRUE  instead of evaluating  COUNTIF Windows 7 64bit IF formula returns  TRUE  instead of evaluating  COUNTIF Office 2010 64bit
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To CATALIN.B
Thank you. exactly what I wanted.
COLIN.
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