You could also use:
Find = ([!0-9^13]@)( )(<[0-9]{4})^13 or ([!^13 ]@ [! ]@)( )([0-9]{4})^13
Replace = \3\2\1^p
The reason '(*) (*) (<[0-9]{4}>)^13' doesn't work, is that * represents a string of any content and length. That content could include paragraph breaks and spaces, which is self-defeating.
__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]
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