Works perfect John. Would have been so much easier if PPT had the ACOS like excel, found that out in my readings trying to find a solution.
So I guess using Pythagorean Theorem (Me.indv.Text = Sqr((Val(Me.indx ^ 2)) - (Val(Me.indh ^ 2)))) in my original post was indeed the easiest way to solve for the side opposite (Vertical component of the triangle) after all.