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Old 08-14-2024, 10:08 AM
vivka vivka is offline Windows 7 64bit Office 2016
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Join Date: Jul 2023
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Hi, Shelley Lou! I have made minor changes to your last code (I think they are justified; see comments). Seems to work properly. However only God knows...
Code:
Sub FormatManualNumbering()

Dim rng As range
Dim rngEnd As Long
    
    Application.ScreenUpdating = False
    Set rng = ActiveDocument.range
    rngEnd = rng.End
    ActiveDocument.range.InsertBefore vbCr
       With rng.Find
        .ClearFormatting
        .Replacement.ClearFormatting
        .Forward = True
        .Wrap = wdFindStop
        .Format = False
        .MatchWildcards = False
'Remove spaces starting paras:
        .text = "^p^w"
        .Replacement.text = "^p"
        .Execute Replace:=wdReplaceAll
'Remove spaces before para signs:
        .text = "^w^p"
        .Replacement.text = "^p"
        .Execute Replace:=wdReplaceAll
'Remove empty paras:
        .MatchWildcards = True
        .text = "^13{2,}"
        .Replacement.text = "^p"
        .Execute Replace:=wdReplaceAll
'Insert a tab before any 1st letter in a para:
        .text = "(^13[!^13]@)([A-Za-z])"
        .Replacement.text = "\1^t\2"
        .Execute Replace:=wdReplaceAll
'Replace two tabs with one tab:
        .text = "^t^t"
        .Replacement.text = "^t"
        .Execute Replace:=wdReplaceAll
'Delete tabs between letters, which have been inserted using
'the code to insert a tab before any 1st letter in a para previously:
        .text = "([A-Za-z])^t([A-Za-z])"
        .Replacement.text = "\1\2"
        .Execute Replace:=wdReplaceAll
    End With
'Running the next Find-Replace causes run-time error 5623
'(The Replace With text contains a group number which is out of range)
'which may occur because the parameters of Find-Replace may be kept in the next use of Find-Replace.
'Resetting rng is one of the ways to correct the error:
    Set rng = ActiveDocument.range
    Do
        With rng.Find
            .ClearFormatting
            .Replacement.ClearFormatting
            .Forward = True
            .Wrap = wdFindStop
            .Format = True
            .MatchWildcards = True
'Find a str between a tab & the nearest previous para sign, i.e.
'a str between a para sign & a tab, excluding other paras in-between:
            .text = "^13[!^13]@^t"
            If .Execute And rng.End <= rngEnd Then
                .text = "[,:; ]"
                .Replacement.text = "."
                .Execute Replace:=wdReplaceAll
            Else: Exit Do
            End If
'Delete all periods immediately before a tab:
            While rng.Characters.Last.Previous = "."
                rng.Characters.Last.Previous.Delete
            Wend
            rng.Collapse wdCollapseEnd
        End With
    Loop
'Reset rng (see the comment above):
    Set rng = ActiveDocument.range
    With rng.Find
         .ClearFormatting
        .Replacement.ClearFormatting
        .Forward = True
        .Wrap = wdFindStop
        .Format = True
        .MatchWildcards = True
'Insert periods after lone 1st-level numberings:
        .text = "(^13[0-9]{1,})^t"
        .Replacement.text = "\1.^t"
        .Execute Replace:=wdReplaceAll
'Delete extra periods in the doc:
        .text = "[.]{2,}"
        .Replacement.text = "."
        .Execute Replace:=wdReplaceAll
'Delete tab after opening bracket:
        .text = "(^13[(])^t"
        .Replacement.text = "\1"
        .Execute Replace:=wdReplaceAll
'Delete tab after opening double quote (Chr(34) & Chr(147))
'after para marks:
        .text = "(^13" & "[" & Chr(34) & Chr(147) & "]" & ")^t"
        .Replacement.text = "\1"
        .Execute Replace:=wdReplaceAll
    End With
'Delete the doc's starting para sign inserted previously:
    ActiveDocument.range.Characters.First.Delete
 Application.ScreenUpdating = True
Set rng = Nothing
End Sub

Last edited by vivka; 08-15-2024 at 01:18 AM.
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