Hi again, Shelley Lou! I think we did it at last! The code has bloated but it works properly in (as I think) all possible cases (see the attached test doc modified by me).
Code:
Sub FormatManualNumbering()
'In active doc, format multi-level manual numbering.
Dim rng As range
Dim rngEnd As Long
Application.ScreenUpdating = False
Set rng = ActiveDocument.range
rngEnd = rng.End
rng.Characters.First.InsertBefore Chr(13)
With rng.Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindStop
.Format = True
.MatchWildcards = True
.text = "(^13[!^13]@)([A-Za-z])"
.Replacement.text = "\1^t\2"
.Execute Replace:=wdReplaceAll
.text = "^t^t"
.Replacement.text = "^t"
.Execute Replace:=wdReplaceAll
End With
Do
With rng.Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindStop
.Format = True
.MatchWildcards = True
.text = "^13[!^13]@^t"
If .Execute And rng.End <= rngEnd Then
.text = "[,:; ]"
.Replacement.text = "."
.Execute Replace:=wdReplaceAll
Else: Exit Do
End If
If rng.Characters.Last.Previous = "." Then
rng.Characters.Last.Previous.Delete
End If
rng.Collapse wdCollapseEnd
End With
Loop
Set rng = ActiveDocument.range
With rng.Find
.ClearFormatting
.Replacement.ClearFormatting
.Forward = True
.Wrap = wdFindStop
.Format = True
.MatchWildcards = True
.text = "(^13[0-9]{1;})^t"
.Replacement.text = "\1.^t"
.Execute Replace:=wdReplaceAll
End With
ActiveDocument.range.Characters.First.Delete
Application.ScreenUpdating = True
Set rng = Nothing
End Sub