Quote:
Originally Posted by macropod
You could use a wildcard Find/Replace, where:
Find = ^32\(p[!\)]@\)
Replace = nothing
No macros required.
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Paul, your understanding of wildcards far exceeds mine. However, the above replaces (p. 2) and (paragraph 24) but not (pp. 3-7). Is a period needed?
Find = ^32\(p.[!\)]@\)
Replace = nothing
followed by
Find = ^32\(pp.[!\)]@\)
Replace = nothing
Andrea:
For more on
wildcards.
Here is a
white paper on the subject.
The searches are looking for a space before the first open parenthesis. If your attorney is at all like me and there are any where there is not a space first, they will not be replaced. To take care of that, you could take the ^32 out of the search strings in a cleanup.
Also, remember that wildcard searches are case-sensitive so these will not find (P. 23).