Try:
str = Split(.Tables(i).Cell(2, 1).Range.Text, vbCr)(0)
As for 'Left(str, len(str) - 1)', you'd need to use 'Left(str, len(str) - 2)', since cells are terminated by a Chr(7) & Chr(13) pair.
__________________
Cheers,
Paul Edstein
[Fmr MS MVP - Word]
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